Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is

we have

substitute

Solve for x
subtract 30 both sides


Divide by 11 both sides

The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10

The circumcenter of a triangle is the point in the plane equidistant from the three vertices of the triangle. so I believe it is A. True..
Got this from someone else but it answers your question
O f(x) = -x-1
Step-by-step explanation:
We want to isolate the 'y' variable, so we will subtract 7 from both sides.
y = x + 6 - 7
y = x -1
also can u please give me brainliest
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54
remember if we can do
xy=0 then assume x and y=0
so factor
0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is
if you have
ax^2+bx+c=0 then
x=

x^2+7x+18
a=1
b=7
c=18
x=

x=

x=

i=√-1
x=

the zerose would be
x=

or