Answer: D) helium.
Explanation:
Nuclear fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.
Nuclear fusion is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.
Example: 
Thus when deuterium and tritium , the two isotopes of hydrogen are fused, a heavier nuclei helium is being formed from two smaller nuclei releasing a neutron.
The solution is the mixture of the solute into the solvent particles. In 60 mL solution, 59.8 mL of solvent is added.
<h3>What are solute and solvent?</h3>
Solute and solvent are the components of a solution. They react and mix together to produce a homogenous mixture. The solute is a substance that is added to the solvent.
Solvents are substances that dissolve the added solute in them to make a homogenous solution.
Given,
Volume of Solute = 0.20 mL
Volume of Solution = 60 mL
The volume of solvent is calculated as:
Volume of solvent = Volume of solution - Volume of solute
= 60- 0.20
= 59.8 mL.
Therefore, 59.8 mL of solvent is present in 60 mL of solution.
Learn more about solute and solvent here:
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The redshift<span> of distant </span>galaxies<span> means that the Universe is probably </span>expanding. If we then go back far enough in time, everything must have been squashed together into a tiny dot and the rapid eruption from this tiny dot was the Big Bang. Another piece of evidence could be that because light takes a long time to travel across the Universe, when we look at very distant galaxies or stars we are also looking back in time. This shows us that galaxies a long time ago were quite different from those today, showing that the Universe has changed. This fits better with the Big Bang theory than the Steady State theory
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
