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Alexandra [31]
3 years ago
11

Consider the hydrocarbon below. 2 carbons are double-bonded to each other; the pair are single bonded to h above left, above rig

ht, below right, and below left. what is the name of this hydrocarbon? propene pentene butene ethene
Chemistry
1 answer:
MissTica3 years ago
4 0

Answer:

\textbf{ \huge\boxed{ \sf ETHENE}}

Explanation:

As the above statement says two carbon atoms are bonded to each other with double bond, the suffix used for double bond is -ene & the prefix for two carbon atoms is eth- & it says four Hydrogen atoms are attached to carbons, 2 Hydrogens to each carbon above & below.

When we draw the structural formula it comes out that the molecule is ethene.

<em>Look at image for more </em><em>clarification</em>

<em>Thanks for joining brainly community!</em>

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Planets close to a star will have __ orbital velocities than planets farther from a star.
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Answer:

The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

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What condition must be met for a battery to be rechargeable?
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Answer:

D. The electrochemical reaction of the battery must be reversible.

Explanation:

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Which of the following terms refers to the number of moles of solute per liter of solution?
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Molarity
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4 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

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4 years ago
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