Answer:
See explanation
Explanation:
When a helium blimp rises in the atmosphere, a point eventually comes when the buoyancy of the blimp compared to the air it displaces is no longer greater than gravity's pull on the blimp hence it stops rising.
A smaller blimp will rise more than a larger blimp at the same pressure because the weight of the blimp determines the altitude to which it will rise.
PH = - log [ H+ ]
pH = - log [ 8.2 x 10⁻⁴]
pH = 3.08
hope this helps!
Answer:
a) dispersion forces, dipole-dipole forces, hydrogen bonds
b) dispersion forces
c) ion-ion interparticle forces, hydrogen bonds, dipole-dipole forces
d) metallic bonds
Explanation:
The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles(Chem Purdue). Dipole forces exists in all molecules but not in metals.
The intermolecular forces present in each substance must be broken before the stated process can occur.
The nature of intermolecular forces in each substance has been shown in the answer section.
For ammonia, the dispersion forces, dipole-dipole forces and hydrogen bonds must be degraded before liquid ammonia begins to boil.
For solid phosphorus which is non polar, only dispersion forces needs to be broken.
To dissolve CsI in HF, ion-ion interparticle forces of CsI must be broken while the dipole-dipole forces, dispersion forces and hydrogen bonds between HF molecules must be broken.
Potassium metal is a pure metal hence only metallic bonds must be broken in order to melt the solid.
Answer:
Explanation:
given that
mass of Ba(NO3)2 = 1.40g
mass of NH2SO3H = 2.50 g
1)to determine the mole of Ba(NO3)2
2) to determine the mass of all three product formed in the reaction
reaction
Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3
<u>Solution</u>
we calculate the molar mass of each species by using their atomic masses
BA = 137.33g/mol
N = 14g/mol
O= 16g/mol
H = 1g/mol
S = 32g/mol
calculation
Ba(NO3)2 = Ba + 2N + 6O
= 137.33 + 2X 14 + 6 X 16
= 261.33g/mol
NH2SO3H = N + 3H + S+ 3O
=14 + 3X1 + 32 + 3X 16
= 97g/mol
Ba(NH2SO3)2 = Ba + 2N + 4H +2S +6O
= 137.33 + 2 X 14 + 4 X1 + 2X32 + 6 X 16
= 329.33g/mol
HNO3 = H + n + 3O
= 1 + 14 + 3 X 16
= 63g/mol
