Answer:
0.04395604395
Step-by-step explanation:
Answer:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) = (0.9938)^10
Step-by-step explanation:
Since the annual rainfall is normally distributed,
Given: that
Mean (µ )= 40
and σ = 4.
Let X be normal random variables of the annual rainfall.
P(that there will be over 10 years or more before a year with a rainfall above 50 inches)
P(>50) = 1-P[X ≤50]
1 - P[X- μ/σ ≤ 50 - 40/4]
=1 - P [Z≤ 5/2]
=1 -Φ(5/2)
=1 - 0.9939
= 0.0062
P( the non occurrence of rainfall above 50 inches)
= 1-0.0062
=0.9938
ASSUMPTION:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) =
To answer this question what you should do is to take 80% out of 95. To do this, you must make a simple rule of three which you can do as follows.
95 ---> 100
x ----> 80
Clearing x we have
x = ((80) / (100)) * (95) = 76
answer
they did make 76 shots of 95
Maybe A yep I’m thinking A
You have lost 5 cards.
In a normal deck of cards, there are 52 cards. If you take those 5 cards away, you have 47 cards.
If you are playing with 3 other people (meaning 4 people total), each person gets 11 cards (totaling 44 cards) and leaving 3 cards left over.
If you are playing with 2 other people (3 people total), each person gets 15 cards (totaling 45 cards) and leaving 2 cards left over.
If you are playing with 4 other people (5 people total), each person gets 9 cards (totaling 45 cards) and leaving 2 cards left over.
Thus meaning, you have lost 5 cards. I hope this helps!