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3 years ago

A pizza with a 30cm diameter is cut up into slices.

Mathematics

1 answer:

Alina [70]3 years ago

3 0

Answer:

28.274333882308138

Step-by-step explanation:

I think it's correct..

I divided 30cm by 50% and then put 6 into a pizza area calculator and came up with this answer.e

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One batch of cookies calls for 2 cups of oil, 4 cups of sugar, 1.5 cups of sugar, 1 cup of baking soda, and 1 cup of chocolate c

hichkok12 [17]

He can make 2 batches of cookies. I'm not sure about the leftover cups because you wrote sugar twice

4 0

3 years ago

A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 3x + 2z = 1 Which of the fo

solong [7]

A) multiply equation A by -2 so you get -2x - 2z = -12 and then you can add both equations to eliminate z

8 0

3 years ago

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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago

Anybody knows what is -2(g - 3) = 2(g - 7)

Veronika [31]

Answer:

g = 4.6

Step-by-step explanation:

-3(g - 3) = 2(g - 7)

-3g + 9 = 2g - 14

-3g = 2g - 23

-5g = -23

g = 4.6

3 0

3 years ago

Which values represent solutions to the equation?

AleksAgata [21]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers