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3 years ago

The solutions to the inequality ys-x+1 are shaded on

Mathematics

1 answer:

kupik [55]3 years ago

6 0

Answer:

the solutions to the inequality ys-x+1 are shaded on the graph. which point is B. (3 ,-2)

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Pls help meh... I need help

sertanlavr [38]

In a parallelogram, opposite angles are congruent and consecutive angles are supplementary.

3x - 15 = 2x + 24
3x - 2x = 24 + 15
x = 39 <===

6 0

3 years ago

Read 2 more answers

Determine whether the triangles must be congruent. If so, name the postulate or theorem that justifies your answer. If not, expl

Alona [7]

Problem 16)

We use ASA (angle side angle) to show the two triangles are congruent. Why ASA instead of AAS? Because the single pair of sides are between the two angles.

--------------------------------------------

Problem 18)

Similar to problem 16, we'll have two pairs of congruent angles, and a pair of congruent sides. However, the sides are NOT between the two angles. So that means we use AAS in this case.

6 0

3 years ago

HOW can you decide whether a relationship is linear by studying the pattern in a data table?

abruzzese [7]

For a relationship to be linear, there must be a constant rate of change. To check this, you need to calculate the equation of the line.
A linear line will always have an equation in the following pattern:
y = mx + c where m is the slope and c is a constant.
This equation must be of first degree (highest power is x^1) to be linear.

Note:
the slope can be calculated using two points (x1,y1) and (x2,y2) as follows:
m = (y2 / y1) / (x2 - x2)
You can then use points from the table and substitute in the equation to calculate the value of c.

4 0

3 years ago

100×1.46= cash exhange

liq [111]

Answer:

$\dashrightarrow \sf \: 100 \times 1.46 \\ \\ \dashrightarrow \sf \: \cancel{100} \times \frac{146}{ \cancel{100 }} \\ \\ \dashrightarrow \sf \: 146$

3 0

3 years ago

A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution

salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

Let p = percentage of the fleet that was out of compliance.

SO, Null Hypothesis, $H_0$ : p = 30% {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = percentage of the fleet out of compliance = $\frac{4}{25}$ = 16%

n = sample of systems tested = 25

So, test statistics = $\frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }$

= -1.909

The value of the test statistics is -1.909.

Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0

3 years ago