Vertical Asymptotes:
x
=
7
x
=
7
Horizontal Asymptotes:
y
=
2
y
=
2
No Oblique Asymptotes
Answer:
Part A: (2x−5)(x+2)
Part B: (5/2,0) and (-2,0)
Part C: The graph of f(x) has both "ends" of the graph pointing upward. You can describe this as heading toward infinity.
Part D: To graph function we can use x-intercepts and "ends" to sketch.In order to graph better use one more point of parabola that you can find as the average of x-intercepts: (-2+5/2)/2 =1/4.This is just x coordinate and you need to plug in 1/4 in the f(x) and find y coordinate -10 1/8. You can use y-intercept (0,-10) as well to graph.
Step-by-step explanation:
2x^2-3x-5=y
(2x-5)(x+1)=y
(2x-5)(x+1)=0
2x-5=0
2x=5
x=2.5
x+1=0
x=-1
you have an even degree (2) and a positive coefficient (2)
therefore as x---> -∞, f(x)----> +∞
also, as x----> +∞, f(x)----> +∞
also notice that this is a parabola that opens upwards so both "ends" approach positive infinity
plot the x-intercepts, find the vertex using h=-b/2a and substituting this value into the equation to find k and make a table of values to graph the parabola unless you only want a rough sketch of the graph-you know the x-intercepts and you found the vertex using h=-b/2a
Mark brainliest please.
Answer:b
Step-by-step explanation:
I NEED BOINTS IM
SORRY GOOD LORD BUTTTTTTT MAYBE C
Answer:
18x^2+6
Step-by-step explanation:
2(9x^2+3)
multiply each term in parentheses by 2
2 x 9x^2+2 x 3
calculate product
18x^2+2 x 3
multiply numbers
18x^2+6
