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Nana76 [90]
3 years ago
15

If p(x)=x^2+x+1 and q(x)=3x^2-1, find p(7)

Mathematics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

p(7) = 57

Step-by-step explanation:

Because this is a function, all you have to do is input 7 for x like so:

p(x)=x^2+x+1 --------------->     p(7)=7^2+7+1

                                            so 49 + 8

                                                = 57

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Answer:

The error interval for x is:

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Step-by-step explanation:

The number after rounding off is obtained as:

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We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

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( Because if we have to round off a number present in decimals to n place then if  there is a  number greater than or equal to 5 at n+1 place then it will result to the one higher digit  at nth place on rounding off and won't change the digit if it less than 5 )

        Hence, the error interval is:

            [3.65,3.74]

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