Solve n3 + 2n2 - 15n = 0 by factoring.

2 answers:

azamat3 years ago

5 0

N³ - 2n² - 15n = 0

"n"

n (n² + 2n - 15) = 0

n = 0

n² + 2n - 15 = 0

Δ = (2)² - 4(1)(-15)
Δ = 4 + 60 = 64

n' = (-2+8) / 2 = 6/2 =3
n'' = (-2-8) / 2 = -10/2 = -5

Solution:

S {-5 , 0 , 3 }

Naily [24]3 years ago

5 0

N^3+2n^2-15n=0

n(n^2+2n-15)=0

n(n^2+5n-3n-15)=0

n(n(n+5)-3(n+5))=0

n(n-3)(n+5)=0

n={-5, 0, 3}

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Read 2 more answers

Graph the function -2x+5y=10

loris [4]

An equation of the form ax+by+c=0, where x, y are variable, and a, b, c are numbers, is called a "linear equation"

the reason we call it linear, is that all solutions (x, y) to this equation, when plotted in the x-y axis, form a line.

To draw this line, 2 points are enough, that is 2 solutions (x, y) of the equation.

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-2x+5y-10=0 is a linear equation (a=-2, b=5, c=-10)

to find 2 solutions, we set x or y any value we want, and solve for the other

for example:

let x=0,

then

-2x+5y-10=0 becomes 5y-10=0, so y=2

this gives us the solution (0, 2)

another example; set y=0

then -2x+5y-10=0 becomes -2x-10=0; -2x=10 so x=-5

thus another solution is (-5, 0)

Draw these 2 points, and join them with a line, as shown in the figure.