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3 years ago

Okay, I have a question, so somebody should have an answer right? what is a orchid?

Chemistry

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

The Orchidaceae are a diverse and widespread family of flowering plants, with blooms that are often colourful and fragrant, commonly known as the orchid family

Explanation:

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49 POINTS!!! PLEASE HELP ME HURRY!!!<br><br> Find the volume of each figure to the nearest tenth.

nikdorinn [45]

V = L x W x H

V = 11 x 5 x 6

V = 330

5 0

3 years ago

Read 2 more answers

What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu

vladimir2022 [97]

Answer: 323.61 g of $Ag$ will be produced

Explanation:

The given balanced chemical reaction is :

$Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag$

According to stoichiometry :

2 moles of $AgNO_3$ require 1 mole of $Cu$

Thus 3.00 moles of $AgNO_3$ will require= $\frac{1}{2}\times 3.00=1.50moles$ of $Cu$

Thus $AgNO_3$ is the limiting reagent as it limits the formation of product.

As 2 moles of $AgNO_3$ give = 2 moles of $Ag$

Thus 3.00 moles of $AgNO_3$ give = $\frac{2}{2}\times 3.00=3.00moles$ of $Ag$

Mass of $Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g$

Thus 323.61 g of $Ag$ will be produced from the given moles of both reactants.

3 0

3 years ago

When a warm air mass is caught between two cooler air masses and the thicker cold air masses move underneath the thinner warm ai

almond37 [142]

An occluded front forms when a warm air mass is caught between two cooler air masses. The warm air mass is cut ofl or occluded' from the ground. The occluded warm front may cause clouds and precipitation. A swirling center of low air pressure is called a cyclone.

6 0

3 years ago

Read 2 more answers

Label each of the descriptions below as theoretical

anzhelika [568]

Answer:

Before performing chemical reactions, it is helpful to know how much product will be produced with given quantities of reactants. This is known as the theoretical yield. This is a strategy to use when calculating the theoretical yield of a chemical reaction. The same strategy can be applied to determine the amount of each reagent needed to produce a desired amount of product.

Explanation:

Reagent Examples

Reagents may be compounds or mixtures. In organic chemistry, most are small organic molecules or inorganic compounds. Examples of reagents include Grignard reagent, Tollens' reagent, Fehling's reagent, Collins reagent, and Fenton's reagent. However, a substance may be used as a reagent without having the word in its name.

3 0

3 years ago

Read 2 more answers

6. Under standard-state conditions, what spontaneous reaction will occur in aqueous solution among the ions Ce4+, Ce3+, Fe3+, an

xz_007 [3.2K]

Answer:

ΔG° = -80.9 KJ

Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

Explanation:

1) Reduction potentials

First of all one should look up the reduction potentials for the species envolved:

$Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

$Fe^{3+} + e$ → $Fe^{2+}$ E°red=0.771V

2) Redox pair

Knowing their reduction pontentials one can determine a redox pair: one species must oxidate while the other is reducing. <u>Remember: the table gives us the reduction potential, so if we want to know the oxidation potential all that has to be done is reverce the equation and change the potencial signal (multiply to -1).</u>

1) $Ce^{4+}$ reduces while $Fe^{2+}$ oxidates

(oxidation) $Fe^{2+}$ → $Fe^{3+} + e$ E°oxi=-0.771V

(reduction) $Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

(overall equation) $Fe^{2+}+Ce^{4+}$ → $Ce^{3+}+Fe^{3+}$ E°=Ereduction + Eoxidation= 1.61 v+(-0.771 v) = 0.839v

The cell potential can also be calculated as the cathode potencial minus the anode potential:

E° = E cathode - E anode =1.61 v - 0.771 v=0.839 v

3) Gibbs free energy and Equilibrium constant

ΔG°=-nFE°, where 'n' is the number of electrons involved in the redox equation, in this case n is 1. 'F' is the Faraday constant, whtch is 96500 C. E° is the standard cell potencial.

ΔG°=-nFE°=-1*96500*0.839

ΔG° = - 80963 J = -80.9 KJ

The Nerst equation gives us the relation of chemical equilibrium and Electric potential.

E=E°- $\frac{RT}{nF} Ln Q$

Where 'R' is the molar gas constant (8.314 J/mol)

It's known that in the equilibrium E=0, so the Nerst equation, at equilibrium, becomes:

E°= $\frac{RT}{nF} Ln K$

Isolating for 'K' gives:

$K=e^{\frac{nFE^{o} }{RT} }$

This shows that 'K' is a fuction of temperature. Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

6 0

4 years ago