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aev [14]
3 years ago
6

What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu

+ 2AgNO3→Cu(NO3)2+ 2Ag
Chemistry
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

You might be interested in
How many particles are in 2.50 moles of iron (II) chloride?
liq [111]

Answer:

<h2>1.505 × 10²⁴ particles</h2>

Explanation:

The number of particles in iron (II) chloride can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.5 × 6.02 × 10²³

We have the final answer as

<h3>1.505 × 10²⁴ particles</h3>

Hope this helps you

8 0
3 years ago
A gas has a temperature of 14 °C, and a volume of 4.5 liters. If the temperature is raised to 29
Ierofanga [76]

The new volume of the gas wii be 4.7 liters.

7 0
3 years ago
Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
3 years ago
What is the molar concentration of Pb+ in a solution that contains 6.73 ppm of
Katarina [22]

Answer:

2.03 × 10⁻⁵ M

Explanation:

Step 1: Given data

Concentration of Pb(NO₃)₂: 6.73 ppm = 6.73 mg/L

Step 2: Convert 6.73 mg/L to mol/L

The molar mass of 331.2 g/mol.

6.73 × 10⁻³ g/L × 1 mol/331.2 g = 2.03 × 10⁻⁵ mol/L = 2.03 × 10⁻⁵ M

Step 3: Calculate the molar concentration of Pb²⁺

Let's consider the ionization of Pb(NO₃)₂.

Pb(NO₃)₂(aq) ⇒ Pb²⁺(aq) + 2 NO₃⁻(aq)

The molar ratio of Pb(NO₃)₂ to Pb²⁺ is 1:1. The molar concentration of Pb²⁺ is 1/1 × 2.03 × 10⁻⁵ M = 2.03 × 10⁻⁵ M.

8 0
3 years ago
The original concentration in a sample is 5.1 x 10^9 cfu/ml. which sample volume should yield a countable plate
poizon [28]

The original concentration is 5.1 × 10⁹ CFU / ml

In order to attain a countable plate, the number of CFU must be present in between 10 and 200 per ml.

Let us take 0.1 ml and dilute it to 1 ml.

This minimizes the concentration to 5.1 × 10⁹ × 10⁻¹ = 5.1 × 10⁸ CFU/ml

In order to minimize the concentration in between 10 and 200, it can be reduced to 5.1 × 10¹

The final concentration = 5.1 × 10¹ CFU/ml

Initial concentration = 5.1 × 10⁹ CFU/ml

Volume of sample with 5.1 × 10¹ CFU = 5.1 × 10¹ CFU × (1 ml / 5.1 × 10⁹ CFU)

= 1.0 × 10⁻⁸ ml

This is the volume to be taken to obtain countable value, 51 CFU.

6 0
3 years ago
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