Question

What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu + 2AgNO3→Cu(NO3)2+ 2Ag

Answer 1

Answer: 323.61 g of $Ag$ will be produced

Explanation:

The given balanced chemical reaction is :

$Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag$

According to stoichiometry :

2 moles of $AgNO_3$ require 1 mole of $Cu$

Thus 3.00 moles of  $AgNO_3$ will require=$\frac{1}{2}\times 3.00=1.50moles$  of $Cu$

Thus $AgNO_3$ is the limiting reagent as it limits the formation of product.

As 2 moles of $AgNO_3$ give =  2 moles of $Ag$

Thus 3.00 moles of $AgNO_3$ give =$\frac{2}{2}\times 3.00=3.00moles$  of $Ag$

Mass of $Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g$

Thus 323.61 g of $Ag$ will be produced from the given moles of both reactants.