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aev [14]
3 years ago
6

What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu

+ 2AgNO3→Cu(NO3)2+ 2Ag
Chemistry
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

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