Answer:
yes, the triangle are congruent by SAS
The answer would be 73 remainder 0 if rounded to one decimal place
The answer to your problem is -1x.
Let x be the number of people that can be seated.
The value of x is some number 0 or greater, such that this number is a whole number (we can't have half a person). This means that
![x \ge 0](https://tex.z-dn.net/?f=x%20%5Cge%200)
which is the same as saying
![0 \le x](https://tex.z-dn.net/?f=0%20%5Cle%20x)
The instructions state that we can seat up to 1200 people. This is the max capacity. We can't go over this amount. So we will also have
![x \le 1200](https://tex.z-dn.net/?f=x%20%5Cle%201200)
indicating that x can be less than 1200 or equal to 1200.
So putting the two inequalities together, we get
![0 \le x \le 1200](https://tex.z-dn.net/?f=0%20%5Cle%20x%20%5Cle%201200)
Note: if you haven't learned about compound inequalities yet, then the teacher may only want
![x \le 1200](https://tex.z-dn.net/?f=x%20%5Cle%201200)
as the answer.
For (A.) Get a common denominator, 40/12 - 9/12 = 31/12 or (2 and 7/12)
For (B.) Get a common denominator, 24/15 - 10/15 = 14/15 (Simplified)
For (C.) Get a common denominator, 51/30 - 25/30 = 26/30 or (13/15)
For (D.) Get a common denominator, 14/6 - 9/6 = 5/6 (Simplified)
Hope this helps!
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