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butalik [34]
3 years ago
10

Leta Stetter Hollingworth conducted pioneering work on __________. A. identity development in ethnic minorities B. cognitive pro

cesses in animals and humans C. racism and its effects on child development D. adolescent development and gifted children  
Physics
2 answers:
dalvyx [7]3 years ago
7 0

This is the only answer in the choices.

D. adolescent development and gifted children  

rusak2 [61]3 years ago
5 0
I believe the correct answer from the choices listed above is option D. Leta Stetter Hollingworth conducted pioneering work on adolescent development and gifted children. She <span>was an American psychologist who conducted pioneering work in the early 20th century. </span>
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The diagram below shows waves A and B in the same medium
cluponka [151]

Answer:

2) twice the amplitude and half the wavelength

Explanation:

3 0
3 years ago
What is the frequency of sound waves whose wavelength is 0.25 m on a day when the air temperature is 25 degree Celsius? Group of
Dvinal [7]

Answer:1384 Hz

Explanation:

Given

wavelength(\lambda )=0.25 m

Temperature T=25^{\circ}

at T=25^{\circ} velocity of sound is 346 m/s

and we know

velocity=frequency\times \lambda

v=f\times \lambda

346=f\times 0.25

f=1384 Hz

5 0
3 years ago
Read 2 more answers
If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
Irina-Kira [14]
The correct answer is B. <span>0.002010812m3. Good Luck! :)</span>
5 0
3 years ago
A one-dimensional plane wall of thickness 2l= 100 mm experiences uniform thermal energy generation of q˙= 800 w/m3 and is convec
slega [8]

Answer:

The thermal conductivity of the wall = 40W/m.C

h = 10 W/m^2.C

Explanation:

The heat conduction equation is given by:

d^2T/ dx^2 + egen/ K = 0

The thermal conductivity of the wall can be calculated using:

K = egen/ 2a = 800/2×10

K = 800/20 = 40W/m.C

Applying energy balance at the wall surface

"qL = "qconv

-K = (dT/dx)L = h (TL - Tinfinity)

The convention heat transfer coefficient will be:

h = -k × (-2aL)/ (TL - Tinfinty)

h = ( 2× 40 × 10 × 0.05) / (30-26)

h = 40/4 = 10W/m^2.C

From the given temperature distribution

t(x) = 10 (L^2-X^2) + 30 = 30°

T(L) = ( L^2- L^2) + 30 = 30°

dT/ dx = -2aL

d^2T/ dx^2 = - 2a

4 0
3 years ago
What do neon,oxygen and nitrogen have in common?
julsineya [31]
Their Period number is common means their "Principal Quantum Numbers" are same

Hope this helps!
7 0
3 years ago
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