What is a statement that’s summarizes a pattern found in nature

Compare and contrast the lithosphere and the asthenosphere(3 different 2 similarities)

worty [1.4K]

Before comparing and contrasting these layers of Earth, we first define what lithosphere and asthenosphere are.

Lithosphere primarily consists of the outermost layers of the Earth, which are the crust and the uppermost portion of the mantle. Simply, the ground you stepped on is part of earth's lithosphere. On the other hand, asthenosphere comprises of hot and partially molten rock just located at the upper portion of the mantle but just below the lithosphere. Both have similarities and differences, which are as follows:

SIMILARITIES:
- Both are the passageways of earthquakes P-waves (Primary waves) just before it reaches the earth's surface.
- Both are made of the same material (Silicon oxide rocks, which are rich in iron and magnesium)

DIFFERENCES:
- Rocks in lithosphere can bend (it deforms, resulting in fault formations), however, rocks in the asthenosphere, not only bend but also flow (plastic in nature).
- Lithosphere has relatively low temperatures compared to asthenosphere.
- Due to its depth, pressure against rocks in asthenosphere is comparatively higher compared to lithosphere.

8 0

3 years ago

The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i

sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

$F_{net}=T-mg$

Now, from Newton's second law, net force equals mass times acceleration.

$F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)$

Plug in the given values and solve for 'T'. This gives,

$T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N$

Therefore, the tension in the cable is 19387.5 N.

3 0

4 years ago

Attempt 2 You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 15151515 l

Natasha_Volkova [10]

Answer:

v = 28.98 ft / s

Explanation:

For this problem we must solve it in parts, let's start by looking for the speed of the two cars after the collision

In the exercise they indicate the weight of each car

Wₐ = 1500 lb

W_b = 1125 lb

Car B's velocity from v_b = 42.0 mph westward, car A travels east

let's find the mass of the vehicles

W = mg

m = W / g

mₐ = Wₐ / g

m_b = W_b / g

mₐ = 1500/32 = 46.875 slug

m_b = 125/32 = 35,156 slug

Let's reduce to the english system

v_b = 42.0 mph (5280 foot / 1 mile) (1h / 3600s) = 61.6 ft / s

We define a system formed by the two vehicles, so that the forces during the crash have been internal and the moment is preserved

we assume the direction to the east (right) positive

initial instant. Before the crash

p₀ = mₐ v₀ₐ - m_b v_{ob}

final instant. Right after the crash

p_f = (mₐ + m_b) v

the moment is preserved

p₀ = p_f

mₐ v₀ₐ - m_b v_{ob} = (mₐ + m_b) v

v = $\frac{ m_a \ v_{oa} - m_b \ v_{ob} }{ m_a +m_b}$

we substitute the values

v = $\frac{ 46.875}{82.03} \ v_{oa} - \frac{35.156}{82.03} \ 61.6$

v = 0.559 v₀ₐ - 26.40 (1)

Now as the two vehicles united we can use the relationship between work and kinetic energy

the total mass is

M = mₐ + m_b

M = 46,875 + 35,156 = 82,031 slug

starting point. Jsto after the crash

K₀ = ½ M v²

final point. When they stop

K_f = 0

The work is

W = - fr x

the negative sign is because the friction forces are always opposite to the displacement

Let's write Newton's second law

Axis y

N-W = 0

N = W

the friction force has the expression

fr = μ N

we substitute

-μ W x = Kf - Ko

-μ W x = 0 - ½ (W / g) v²

v² = 2 μ g x

v = $\sqrt{ 2 \ 0.750 \ 32 \ 17.5}$ Ra (2 0.750 32 17.5

v = 28.98 ft / s

3 0

3 years ago

Derive the expression for the equivalent resistance of three resistors in[1] paraleli [2] series

sergeinik [125]

The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.

When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.

8 0

4 years ago

Who’s going faster in the attached image?

ioda

Answer:

Art

Explanation:

Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.

8 0

3 years ago

Read 2 more answers