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yKpoI14uk [10]
3 years ago
15

Hi, can someone help me with this? Solve the system of equations: Y= 2x-4 X= y+1

Mathematics
1 answer:
agasfer [191]3 years ago
7 0

Y=2x-4

X=y+1

2(y+1)-4

2y+2-4

2y-6

6=2y

6/2 =2y/2

y=3

x = 3+1

x=4

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A rectangle has a height of a² + 3 and a width of a² + 2a + 5.
valentina_108 [34]

Answer:

Area =  a^4+2a^3+8a^2+6a+15

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

(a+b)(x+y) = ax + ay + bx + by

Thus, we have:

(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15

THis is the expression for area.

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Step-by-step explanation:

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Answer:

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