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prohojiy [21]
3 years ago
15

HELP 14÷(-3.5) A) -4.2 B)(-4) C) 3.8 OR D)4

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
B)-4 UR WELCOMMEEEEEEEEEEEEEEEEEEEEE
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Is this a function or no?
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Answer:

No

Step-by-step explanation:

Positives cannot point at negatives I think.

5 0
3 years ago
5v + 7f =28.70 if f is 2.85
adell [148]
Hey!

First, let's write the problem.
5v+7\left(2.85\right)=28.7
Multiply 7 with 2.85.
5v+19.95=28.7
Subtract 19.95 from both sides.
5v+19.95-19.95=28.7-19.95
5v=8.75
Divide both sides by 5.
\frac{5v}{5}=\frac{8.75}{5}
v=1.75

Let me know if you have any questions regarding this problem!
Thanks!
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An insecticible contains 85 centigrams of inert ingredient for every 1 centigram of active ingredient. if a quantity of the weig
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7 0
3 years ago
Problem PageQuestion
krok68 [10]

Answer:

Jennifer's height is 63.7 inches.

Step-by-step explanation:

Let <em>X</em> = heights of adult women in the United States.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 65 inches and standard deviation <em>σ</em> = 2.4 inches.

To compute the probability of a normal random variable we first need to convert the raw score to a standardized score or <em>z</em>-score.

The standardized score of a raw score <em>X</em> is:

z=\frac{X-\mu}{\sigma}

These standardized scores follows a normal distribution with mean 0 and variance 1.

It is provided that Jennifer is taller than 70% of the population of U.S. women.

Let Jennifer's height be denoted by <em>x</em>.

Then according to the information given:

    P (X > x) = 0.70

1 - P (X < x) = 0.70

    P (X < x) = 0.30

⇒  P (Z < z) = 0.30

The <em>z</em>-score related to the probability above is:

<em>z</em> = -0.5244

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

          z=\frac{X-\mu}{\sigma}

-0.5244=\frac{x-65}{2.4}

          x=65-(0.5244\times 2.4)

             =63.7414\\\approx63.7

Thus, Jennifer's height is 63.7 inches.

3 0
3 years ago
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