Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
According to my guesses, he should have swung the pendulam bob and noted its time period. In order to observe the effect of mass, he would have repeated the experiment with varied pendulam bobs. Hope this helped!
Answer:
dP/dt = 26.12 W/s
Explanation:
First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:
dR₃/dt = 0.552 Ω/s
where,
dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω
dt = time interval = ?
Therefore,
84.28 Ω = (0.552 Ω/s)(dt)
dt = (84.28 Ω)/(0.552 Ω/s)
dt = 152.68 s
Now, we find change in power (dP):
dP = V(R₁ + R₂ + dR₃)
dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)
dP = 3987.71 W
Dividing by dt:
dP/dt = 3987.71 W/152.68 s
<u>dP/dt = 26.12 W/s</u>
Answer:
51. 7m/s
Explanation:
Take speed of sound in air = 340 m/s
fp = fs (V + Vp)/(V + Vs)
128 = 123 (340 + Vp)/(340 + 36.4)
Vp = 51.7m/s
Explanation:
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/.
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = ................ 1
On the Moon, the gravitational force is of that on the Earth.
m x = k x 5.0
= 5k
⇒ k = ............. 2
Equating 1 and 2, we have;
=
m =
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.