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tatiyna
3 years ago
11

which of the following devices is used to create an open circuit? a. Switch b. Bulb c. Battery d. Resistor

Physics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

The answer is

A. Switch

Explanation:

A switch is a device for making and breaking current in an electric circuit, it is mostly made of a non conducting material to prevent the user from being electrocuted, switches comes in range of types depending on the area of applications.

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If the retina is 1.7 cm from the lens in the eye, how large is the image on the retina of a person of height 1.5 m standing 9.0
sineoko [7]

Answer:

The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign

Explanation:

u = Object distance =  9 m

v = Image distance = 1.7 cm (as the image is forming on the retina)

h_u= Object height = 1.5 m

Magnification

m=-\frac{v}{u}=\frac{h_v}{h_u}\\\Rightarrow -\frac{v}{u}=\frac{h_v}{h_u}\\\Rightarrow -\frac{0.017}{9}=\frac{h_v}{1.5}\\\Rightarrow h_v=-0.00283\ m

The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign

4 0
3 years ago
A car moving at 11.6 m/s begins to accelerate at 5.22 m/s/s and reaches a final velocity of 31.5 m/s. How far did it travel duri
mr_godi [17]

Use the kinematic equation,

Vf^2 = Vi^2 + 2aX

31.5^2 = 11.6^2 + 2(5.22)(x)

Solve for x

Answer: 82.2m

8 0
3 years ago
Could you help me please !!!
grandymaker [24]

Answer:

6500g

Explanation:

7000 - 500 = 6500

7 0
3 years ago
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
NARA [144]

The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².                                                                                      

When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:

v_{f_{r}} = v_{i_{r}} + at    

Where:                                                              

v_{f_{r}}: is the final velocity of the rocket

v_{i_{r}}: is the initial velocity of the rocket = 0

a: is the acceleration

t: is the time

After 4 seconds, the <u>final speed of the rocket</u> will be the <u>initial speed of the bolt</u>, so:                                              

v_{f_{r}} = v_{i_{b}} = at = 4a  

When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.        

The<u> initial height of the bolt</u> will be the <u>final height of the rocket</u>, and vice-versa. With this, we can take the final height of the bolt as zero.                        

y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a

Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:

y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2}

194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2}    

a = \frac{194.7}{33.2} = 5.86 m/s^{2}    

   

Therefore, the acceleration of the rocket is 5.68 m/s².

You can find another example of acceleration calculation here: brainly.com/question/24589208?referrer=searchResults

I hope it helps you!                                                                              

3 0
3 years ago
You have arranged that the magnetic field in a particular region of space is due North with a value of 0.0040 T. An electron ent
Anna [14]

Answer:

1. Magnetic force = 4.56*10^-12 N

2. Acceleration = 5.01 *10^18 m/s^2

3. A) The direction of the moving electron will change but its speed will remain constant.

Explanation:

Given Data:

B = 0.0040 T North

q = 1.6*10^-19 C

Mass of electron = 9.1*10^-31 kg

V = 9.5% of speed of light

  = 9.5% *3*10^8

  = 28.5*10^6 m/s  west

So, B and v are perpendicular to each other.

Therefore, ∅ = 90°

1, Calculating the magnetic force using the formula;

F = qvBsin∅

  = 1.6*10^-19 * 28.5*10^6*sin90

  = 4.56*10^-12 N

Therefore, the strength of the force = 4.56*10^-12 N

2. Calculating acceleration using the formula;

F = ma

a = F/m

  = 4.56*10^-12 /9.1*10^-31

  = 5.01 *10^18 m/s^2

3. A) The direction of the moving electron will change but its speed will remain constant.

3 0
3 years ago
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