Question

What is the distance between the points (4,5) and (10,13) on a coordinate plane?

Answer 1

The distacne between the points (x1,y1) and (x2,y2) is
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so

$D=\sqrt{(10-4)^2+(13-5)^2}$
$D=\sqrt{(6)^2+(8)^2}$
$D=\sqrt{36+64}$
D=√100
D=10
the distance is 10 units