Kyla makes a triangular school pennant. The area of the
triangle is 180 square inches. The base of the pennant is z inches long. The
height is 6 inches longer than twice the base length. The base and height can
be solve using the formal A =bh/2
Since b = z and h = 6 + 2z
180 = z(6+2z) /2
B =Z =12 in
H = 30 in
Well, if both Alexis and Tara mine salt for 40 hours... they'd have mine 1,000 pounds of salt. Is this what you were looking for?
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
![5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}](https://tex.z-dn.net/?f=5%5Cleft%28x%2B27%5Cright%29%5Cge%20%5C%3A6%5Cleft%28x%2B26%5Cright%29%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5C%3A-21%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-21%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:
- <em>greater than or equal </em>is written as:
- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer:
60 degress
Step-by-step explanation:
How I got it:
1. Find out the angel of each side. 360 divded by 6 = 60
2. Get the answer of 60
Advice:
-Make an polygon using paper and rotate it. (Use protractor and ruler if your gonna do it)
Answer:
(0,4)
Step-by-step explanation:
This is an exponential function so y = 4( 3^x) will have a y-intercept when x=0.
y = 4 (3^0) = 4*1 = 4
The y-intercept is (0,4).
