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faust18 [17]
3 years ago
9

Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero el

ectric field and a uniform magnetic field. The particles start at rest from the same position (but at different times; they do not interact with each other). They have identical charges, but different masses. Particle 2 has a cyclotron radius 1.5 times as large as that of particle 1. Find ratio m2/m1
Physics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

Explanation:

In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .

The velocity with which they will come out of electric field can be measured from following equation

Eq = 1/2 m v²  , E is electric field , q is charge on the particle , m is mass and v is velocity .

v² = 2Eq / m

radius of circular path can be measured by the following expression

m v² / r = Bqv

2Eq / r = Bqv

r = 2Eq / Bqv

= 2E / Bv

r² = 4E² / B²v²

= 4E²m / B²x 2Eq

since E , B and q are constant

r² = K . m

r₂² / r₁² = m₂ / m₁

1.5²

m₂ / m₁ = 1.5²

= 2.25

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85.5 km/h

Explanation:

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v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

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average speed is given as

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v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

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4 years ago
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b)

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Answer: false

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The answer to the question is false. Hope this helps you!

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