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tiny-mole [99]
3 years ago
15

Explain how airplane wings and the wings of birds affect the air flowing over them to produce lift

Physics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
Because the air in their wings helps them fly
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At the second maxima on either side of the central bright spot in a double-slit experiment, light from
Alex

Answer:

Option 3 is the correct option to the following question.

Explanation:

Double slit experiment:

The double-slit experiment in modern physics reveals that light and matter can exhibit characteristics of both classically described waves and particles; it also shows the inherently probabilistic existence of quantum mechanical phenomena.  

When two wavelength meets ,if the resultant amplitude is maximum then this is known as constructive interference and the resultant amplitude is maximum then this is known as destructive interference.

Therefore the answer is "3".

5 0
4 years ago
A 282 kg bumper car moving 3.50 m/s collides with a 155 kg bumper car moving -1.38 m/s. Afterwards the 282 kg car moves at 1.10
icang [17]

Answer:

4.03 m/s

Explanation:

Initial momentum = final momentum

(282 kg) (3.50 m/s) + (155 kg) (-1.38 m/s) = (282 kg) (1.10 m/s) + (115 kg) v

v = 4.03 m/s

6 0
3 years ago
Read 2 more answers
a child stands with each foot on a different scale. The left scale reads 200N and the right scale reads 150N. what is her mass i
vitfil [10]

Answer:

35.7 kg

Explanation:

We are given that

Left scale reads =200N

Right scale reads=150 N

We have to find the mass in kg.

We know that

Weight  of child= Sum of two scales=200+150=350 N

Acceleration due to gravity=9.8 m/s^2

We know that

Weight= mg

Using the formula

350=9.8 m

m=\frac{350}{9.8}=35.7 kg

Hence, the mass of child=35.7 kg

4 0
3 years ago
If a speed sound in air at o°c is 331m/s. what will be its value at 35 °c​
Lady_Fox [76]

Answer:

352 m/s

Explanation:

The velocity of sound in air is approximated as:

v ≈ 331 + 0.6 T

where v is the velocity in m/s and T is the temperature in Celsius.

At T = 35:

v = 331 + 0.6 (35)

v = 352 m/s

5 0
3 years ago
The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers.
AVprozaik [17]

Answer:

F = 1.63 x 10⁻⁹ N

Explanation:

Complete question is as follows:

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?

Answer:

The gravitational force is given by Newton's Gravitational Law as follows:

F = Gm₁m₂/r²

where,

F = Gravitational Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of each ball = 7 kg

r = distance between balls = 2 m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²

<u>F = 1.63 x 10⁻⁹ N</u>

7 0
3 years ago
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