According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of
2 answers:
Answer:
the inverse of the square of the distance separating them
Explanation:
As we know that two charges are separated by some distance from each other than that force is given as
here we know that
[tex]q_1, q_2[/tex = two different point charges
r = distance between two charges
so here we know from above formula that electrostatic force between two charges depends on the product of two charges and inversely depends on the square of the distance between two charges
so correct answer will be
the inverse of the square of the distance separating them
You might be interested in
Answer:
Explanation:
As we know that average velocity is defined as the ratio of total displacement of the object and its time interval.
so here we can say
now we know that in one complete revolution the total displacement of the tip of the seconds hand is zero
because it will have same position after one complete revolution from where it starts
so here we can say that the average velocity will be zero
When dealing with multiple forces acting on a body, it is advisable to draw a free-body diagram like that shown in the picture. There are four forces acting on the box: weight (W) pointing straight down, normal force perpendicular to the slope denoted as Fn, force used to push the box upwards along the slope and the frictional force acting opposite to the direction of motion of the box denoted as Ff. Frictional force is equal to coefficient of kinetic friction (μk) multiplied with Fn.
∑Fy = Fn - mgcos30° = 0
Fn = (50)(9.81)(cos 16) = 471.5 N
When in motion, the net force is equal to mass times acceleration according to Newton's 2nd Law of Motion:
Fnet = F - μk*Fn - mgsin30° = ma
250 - (0.2)(471.5 N) - (50)(sin 16°) = (50)(a)
a = 2.84 m/s²
∑Fy = Fn - mgcos30° = 0
Fn = (50)(9.81)(cos 16) = 471.5 N
When in motion, the net force is equal to mass times acceleration according to Newton's 2nd Law of Motion:
Fnet = F - μk*Fn - mgsin30° = ma
250 - (0.2)(471.5 N) - (50)(sin 16°) = (50)(a)
a = 2.84 m/s²