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DerKrebs [107]
2 years ago
8

According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of

the objects the inverse of the charges of the objects the inverse of the square of the distance separating them
Physics
2 answers:
exis [7]2 years ago
6 0

The force between two charges objects is related to separation.


IgorC [24]2 years ago
6 0

Answer:

the inverse of the square of the distance separating them

Explanation:

As we know that two charges are separated by some distance from each other than that force is given as

F = \frac{kq_1q_2}{r^2}

here we know that

[tex]q_1, q_2[/tex = two different point charges

r = distance between two charges

so here we know from above formula that electrostatic force between two charges depends on the product of two charges and inversely depends on the square of the distance between two charges

so correct answer will be

the inverse of the square of the distance separating them

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You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
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Which model is most likely used to predict a future event?
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Predictive modeling.
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What happens to light waves at the interface between different media?
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Answer:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Explanation:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Hope this helps.

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Describe how you determine whether an object is in motion
Flauer [41]
An object is in motion when its distance from another object is changing.
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A person hums into the top of a well (tube open at only one end) and finds that standing waves are established at frequencies of
S_A_V [24]

Answer:

Explanation:

The resonance in a tube that is open at one end and closed at the other, we can find it because in the closed part you have a node and in the open part you have a belly, so for the fundamental frequency you have ¼ Lam, the different resonances are:

Fundamental              λ = 4L

3 harmonica               λ  = 4L / 3

5 Harmonica               λ = 4L / 5

General harmonica     λ = 4L / (2n-1)                n = 1, 2, 3

Let's apply this equation to our case

The speed of sound is given by

          v =  λ  f

          λ = v / f

Let's look for wavelengths

         λ₁ = 40.6 / 343 = 0.1184 m

         λ₂ = 67.7 / 343 = 0.1974 m

         λ₃ = 94.7 / 343 = 0.2761 m

Since the wavelengths are close we can assume that it corresponds to consecutive integers, where for the first one it corresponds to the integer n

          λ ₁ = 4L / (2n-1)

          λ₂ = 4L / (2 (n + 1) -1) = 4L / (2n +1)

          λ₃ = 4L / (2 (n + 2) -1) = 4L / (2n + 3)

Let's clear in the first and second equations

          2n-1 = 4L / λ₁

          2n +1 = 4L / λ₂

Let's solve the system of equations

         4L / λ₁ + 1 = 4L / λ₂ -1

         4L / λ₂ – 4L / λ₁ = 2

         2L (1 / λ₂ - 1 / λ₁) = 1

         1 / L = 2 (1 / λ₂ -1 / λ₁)

         1 / L = 2 (1 / 0.1974 - 1 / 0.1184)

         1 / L = 2 (5,066 - 8,446) = -6.76

         L = 0.1479 m

3 0
3 years ago
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