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DerKrebs [107]
3 years ago
8

According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of

the objects the inverse of the charges of the objects the inverse of the square of the distance separating them
Physics
2 answers:
exis [7]3 years ago
6 0

The force between two charges objects is related to separation.


IgorC [24]3 years ago
6 0

Answer:

the inverse of the square of the distance separating them

Explanation:

As we know that two charges are separated by some distance from each other than that force is given as

F = \frac{kq_1q_2}{r^2}

here we know that

[tex]q_1, q_2[/tex = two different point charges

r = distance between two charges

so here we know from above formula that electrostatic force between two charges depends on the product of two charges and inversely depends on the square of the distance between two charges

so correct answer will be

the inverse of the square of the distance separating them

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ValentinkaMS [17]

The net force on particle particle q1 is 13.06 N towards the left.

<h3>Force on q1 due to q2</h3>

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

<h3>Force on q1 due to q3</h3>

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

<h3>Net force on q1</h3>

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

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Which type of place is rich in biodiversity?​
Vlad1618 [11]

Explanation:

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the answer is Brazil

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If a hockey stick exerts a force of 40 N on a 0.5-kg puck, what will the
antoniya [11.8K]

Answer:

  B.  80 m/s²

Explanation:

F = ma

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3 years ago
The prop blades of an airplane spin with a linear velocity of 875 m/s and have a centripetal acceleration on the farthest edge o
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The radius of the prop blade of an airplane is determined as 4.25 m.

<h3>Radius of the prop blade</h3>

The radius of the prop blade of an airplane is calculated as follows;

a = v²/r

where;

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r = v²/a

r = (875²)/(180,000)

r = 4.25 m

Thus, the radius of the prop blade of an airplane is determined as 4.25 m.

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Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does th
bogdanovich [222]

The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

               the mass of planet B to be, Mₓ = M

               the radius of planet A to be, R₁

               the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁²      - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

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From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

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Thus we get,

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Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

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2 years ago
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