Heya!!
For calculate aceleration, lets applicate second law of Newton:
<u>Δ Being Δ</u>
F = Force = 183 N
m = Mass = 367 kg
a = Aceleration = ?
⇒ Let's replace according the formula and clear "a":
⇒ Resolving
Result:
The aceleration is <u>0,49 meters per second squared (m/s²)</u>
Good Luck!!
Answer:
our acceleration is 0 because there is a constant speed..
a = final speed - initial speed / time
final speed = initial speed ( since speed is constant)
therefore acceleration is 0
Answer:
(a) W=1.20×10⁴J
(b) U= -5.46×10⁴J
(c) Q= -4.26×10⁴J
Explanation:
Given that student does 1.20×10⁴J work
(a) W=1.20×10⁴J
Work done by student,so positive sign
During the process, his internal energy decreases by 5.46×10⁴J.
(b) U= -5.46×10⁴J.
As the Energy decreases therefore negative sign
For (c) Q
We know the formula
