A (b) would be 42 (c) from x to Y mark me as brainlist thanks
Answer:
3.5 N
Explanation:
Let the 0-cm end be the moment point. We know that for the system to be balanced, the total moment about this point must be 0. Let's calculate the moment at each point, in order from 0 to 100cm
- Tension of the string attached at the 0cm end is 0 as moment arm is 0
- 2 N weight suspended from the 10 cm position: 2*10 = 20 Ncm clockwise
- 2 N weight suspended from the 50 cm position: 2*50 = 100 Ncm clockwise
- 1 N stick weight at its center of mass, which is 50 cm position, since the stick is uniform: 1*50 = 50 Ncm clockwise
- 3 N weight suspended from the 60 cm position: 3*60 = 180 Ncm clockwise
- Tension T (N) of the string attached at the 100-cm end: T*100 = 100T Ncm counter-clockwise.
Total Clockwise moment = 20 + 100 + 50 + 180 = 350Ncm
Total counter-clockwise moment = 100T
For this to balance, 100 T = 350
so T = 350 / 100 = 3.5 N
<span>Your answer will be 70,000 kgm/s</span>
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. ... They are hence known as 'electromagnetic' waves. The electric field and magnetic field of an electromagnetic wave are perpendicular (at right angles) to each other.
Hope this helps.
:)
Answer:

Explanation:
Force is the product of mass and acceleration.

We can find mass, since we know the acceleration and force.
The acceleration is 14 meters per square second. The force is 280 Newtons, but we should convert the units to make the problem simpler later on.
- 1 kilogram meter per square second is equal to 1 Newton.
- 280 Newtons are equal to 280 kg*m/s²

Substitute the values into the formula.

We want to solve for the mass or m. Therefore we must isolate the variable on one side of the equation.
m is being multiplied by 14 m/s². The inverse of multiplication is division. Divide both sides of the equation by 14 m/s²


The m/s² will cancel, which is why we converted the units earlier.


The mass of the object is <u>20 kilograms.</u>