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KengaRu [80]
2 years ago
11

Solve the system of equations given below. -5x = y – 5 -2y = -x-21

Mathematics
1 answer:
irakobra [83]2 years ago
3 0

Answer:

<h2>x = -1, y = 10 → (-1, 10)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-5x=y-5&\text{subtract y from both sides}\\-2y=-x-21&\text{add x to both sides}\end{array}\right\\\left\{\begin{array}{ccc}-5x-y=-5&\text{multiply both sides by (-2)}\\x-2y=-21\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x+2y=10\\x-2y=-21\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad11x=-11\qquad\text{divide both sides by 11}\\.\qquad x=-1\\\\\text{put the value of x to the first equation:}\\\\10(-1)+2y=10\\-10+2y=10\qquad\text{add 10 to both sides}\\2y=20\qquad\text{divide both sides by 2}\\y=10

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((-4x^3)(y^4))^-3
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(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)  

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7 0
3 years ago
Given the system of linear equations.
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Part(A):

To solve the system of Linear equations using Substitution:

x+y=7 \\ 2x+y=5

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\mathrm{Subsititute\:}x=7-y

2\left(7-y\right)+y=5

14-2y+y=5

14-y=5

\mathrm{Subtract\:}14\mathrm{\:from\:both\:sides}

14-y-14=5-14

-y=-9

\mathrm{Divide\:both\:sides\:by\:}-1

y=9

\mathrm{For\:}x=7-y

\mathrm{Subsititute\:}y=9

x=7-9=-2.\mathrm{The\:solutions\:to\:the\:system\:of\:equationts\:are:}

y=9,\:x=-2

PArt(B): Use a graph to verify your answer to the system:

Using Desmos graphing calculator, graph the two equations.

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