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elena-s [515]
2 years ago
14

Let a and b be any two integers. Show that the following statement is false: If 3|(a+b),then 3|(a−b).Hint. To show that the stat

ement is false, you need to find two integers a and b for which 3|(a+b) is true and 3|(a−b) is false.
Mathematics
1 answer:
Phoenix [80]2 years ago
3 0

Answer with Step-by-step explanation:

Let a and b are two integers.

We have to show that

if 3\a+b then 3\a-b is false.

In order to prove that given statement is false we prove this with the help of example

Suppose we have two integers a=2 and b=4

if 3\2+4

3\6=2

2-4=-2

But 3 does not divide -2.

Therefore, the given statement is false.

Hence, proved.

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Over 4 days the temperature was 4,6,-12,and -5 degrees.What was the average temperature?
Deffense [45]
The average temperature is -7.



Hope this helps
8 0
3 years ago
What theorem or postulate can be used to justify that two triangles are congruent
kicyunya [14]
You can use the ASA postulate which means angle side angle. if 2 angles and the including side are congruent to the corresponding parts of another triangle then the triangles are congruent. hope that helps :)
4 0
3 years ago
Read 2 more answers
(10 points)
icang [17]
There is a mathematical formula which relates these quantities, given by:

A= \frac{P\times a}{2}

Using this, we have:

<span>A= \frac{P\times a}{2} \\ 484= \frac{(10n)\times 12.1 }{2} \\ \boxed {n=8}</span>
6 0
2 years ago
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work
valina [46]

Answer:

Step-by-step explanation:

Question

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.​

perimeter of a triangle = AB+AC+BC

Using the distance formula

AB = sqrt(-2-5)²+(2-2)²

AB = sqrt(-7)²

AB =sqrt(49)

AB =7

BC = sqrt(-2+2)²+(2-5)²

BC = sqrt(0+3²)

BC =sqrt(9)

BC =3

AC= sqrt(-2-5)²+(2-5)²

AC= sqrt(-7)²+3²

AC =sqrt(49+9)

AC =sqrt58

Perimeter = 10+sqrt58

5 0
2 years ago
Two catalysts in a batch chemical process, are being compared for their effect on the output of the process reaction. A sample o
anzhelika [568]

Answer:

2.083 < µ1 - µ2 < 5.917  

Step-by-step explanation:

We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.

The calculations of the sample means and standard deviations are done for us.

Sample 1: Catalyst 1

n = 12, x = 85, s = 4

Sample 2:  Catalyst 2

n = 10, x = 81, s = 5

See attached photo for the construction of the confidence interval...

3 0
3 years ago
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