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Nadusha1986 [10]
4 years ago
9

Solve the equation by using the substitution method. x^2+ y^2=109, x-7=1/3y^2

Mathematics
1 answer:
Brut [27]4 years ago
4 0
X^2+ y^2=109


x 2 + y2 = 109
Step 1: Add -y^2 to both sides.
x 2 + y2 + − y2 = 109 + − y2
x 2 = − y2 + 109
Step 2: Take square root.
x = − y2 + 109 or x = − − y2 + 109
Answer:
x = − y2 + 109 or x = − − y2 + 109 CALCULATE IT
Solve for Variable


x-7=1/3y^2


x − 7 = 1
3 y2
Step 1: Add 7 to both sides.
x − 7 + 7 = 1
3 y2 + 7
x = 1
3 y2 + 7
Answer:
x = 1
3 y2 + 7
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melamori03 [73]

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3 0
3 years ago
A. x = –4
uysha [10]
Please, please, post only ONE question at a time.  The way Brainly is set up, it's very difficult to conclude one problem and then move on to the next in the same session.

<span>Solve y = log3243.  I must make the assumption here that you mean:

</span><span>Solve y = (log to the base 3) of 243.
</span>
Solve y = (log   243   in better, more compact form.
                      3

If you recognize that 243 is an integer power of 3, the problem becomes much easier.  
                  2             3            4                  5
Note that 3   = 9,    3   = 27, 3   =81, and 3   = 243.

Also note that the log function and the exponential function are inverses of one another, and that inverse functions "undo" each other.
                      x
Thus, log    3     is simply x.
               3
                                           5
Thus, log    243  =  log     3    = 5 (answer).
                3                   3

Please repost the rest of your questions, one at a time, and then I will gladly help you with them.
3 0
4 years ago
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