Question

Solve the equation by using the substitution method. x^2+ y^2=109, x-7=1/3y^2

Answer 1

X^2+ y^2=109


x 2 + y2 = 109
Step 1: Add -y^2 to both sides.
x 2 + y2 + − y2 = 109 + − y2
x 2 = − y2 + 109
Step 2: Take square root.
x = − y2 + 109 or x = − − y2 + 109
Answer:
x = − y2 + 109 or x = − − y2 + 109 CALCULATE IT
Solve for Variable


x-7=1/3y^2


x − 7 = 1
3 y2
Step 1: Add 7 to both sides.
x − 7 + 7 = 1
3 y2 + 7
x = 1
3 y2 + 7
Answer:
x = 1
3 y2 + 7