Question

Find the value ofa.) lim (x²-1)/(x²+1)x−>∞​

Answer 1

Answer:

$\displaystyle\lim_{x \to \infty} \frac{x^2-1}{x^2+1} \\ \text{take x^2 common from numerator and denominator} \\ \displaystyle\lim_{x \to \infty} \dfrac{1-\frac{1}{x^2}}{1+\frac{1}{x^2}} \\\text{Now put the limit}\\\displaystyle\lim_{x \to \infty} \frac{1-0}{1+0}= 1$