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ivann1987 [24]
3 years ago
14

When 5 is added to 2 times a number, the result is 45. find the number.

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0
A.

let the number be n.
2n+5=45
2n=40
n=20
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There are 3 different mathematics courses, 3 different science courses, and 5 different history courses. If a student must take
Damm [24]

Answer:

45 ways

Step-by-step explanation:

We are given;

there are 3 different math courses, 3 different science courses, and 5 different history courses.

Thus;

Number ways to take math course = 3

The number of ways to take science course = 3

The number of ways to take history course = 5

Now, if a student must take one of each course, the different ways it can be done is;

possible ways = 3 x 3 x 5 = 45 ways.

Thus, number of different ways in which a student must take one of each subject is 45 ways.

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3 years ago
The point (1,5) lies in quadrant II of a rectangular coordinate system​
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Answer:

No

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Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't

6 0
3 years ago
Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37
Mandarinka [93]

Answer:

The general rule is a_n = -2 - 5(n-1)

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

a_{n} = a_1 + (n-1)d

In which a_1 is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

a_n = a_m + (n-m)d

a3 = -12 and a8 = -37

First we find the common difference. So

a_n = a_m + (n-m)d

a_8 = a_3 + (8-3)d

-37 = -12 + 5d

5d = -25

d = -\frac{25}{5}

d = -5

So

a_n = a_1 - 5(n-1)

Finding the first term:

a_n = a_1 - 5(n-1)

Since a_3 = -12

a_n = a_1 - 5(n-1)

a_3 = a_1 - 5(3-1)

a_1 = a_3 + 10 = -12 + 10 = -2

So the general rule is:

a_n = a_1 - 5(n-1)

a_n = -2 - 5(n-1)

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