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Neporo4naja [7]
3 years ago
9

An atom can be described as ?????????

Chemistry
2 answers:
siniylev [52]3 years ago
6 0
Hello there.

<span>An atom can be described as ?????????
</span>
<span>The smallest unit of an element</span>
Paladinen [302]3 years ago
3 0
<span>An atom can be described as "Smallest unit of an Element which can exists on its own"

Hope this helps!</span>
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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
Pachacha [2.7K]
The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.
3 0
3 years ago
Which examples best demonstrate the benefit of understanding physical properties?
Veseljchak [2.6K]

Answer:

*Engineers can design better bridges because they know how metal changes shape.

*Scientists can easily classify mixtures of unknown substances.

Explanation:

Tensile strength and the properties of mixtures are physical properties because the substances are not changed into different ones.

A. and C. are wrong. Combustion and other reactions are chemical properties because the substances are changed into different ones

3 0
4 years ago
Read 2 more answers
The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?
siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = K_a=1.9\times 10^{-5}

The equilibrium reaction for dissociation of HN_3 (weak acid) is,

                           HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

Dissociation constant is given as:

K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}

By solving the terms, we get value of (\alpha)}

\alpha=0.00686832

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.002747)

pH=2.56

Therefore, the pH of the solution is, 2.56.

8 0
4 years ago
What is the molarity of 245.0g of h2so4 dissolved in 350ml of solution​
kirill115 [55]
M

350 mL = 0.350 L

245.0g H2SO4 / 98.08 g/mol H2SO4
= 2.5 mol H2SO4

2.5 mol H2SO4 / 0.350 L = 7.14 M
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4 years ago
In a modern periodic table the element are arranged in order of increasing
klemol [59]

Answer:

what are you asking?

Explanation:

7 0
3 years ago
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