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Komok [63]
3 years ago
12

A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Cel

sius + 273 = Kelvin) Use Gay Lussac's Formula to solve. 182 K 192 K 202 K 212 K
Chemistry
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

T₂ = 182 K

Explanation:

Given that,

Initial pressure, P₁ = 120 kPa  

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{80\ kPa\times 273}{120\ kPa}\\\\T_2=182\ K

So, the new temperature is equal to 182 K.

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a. 1.23 V

b. No maximum

Explanation:

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