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4 years ago

Which examples best demonstrate the benefit of understanding physical properties?

Chemistry

2 answers:

Zanzabum4 years ago

4 0

Answer: *Scientists can easily classify mixtures of unknown substances.

*Engineers can design better bridges because they know how metal changes shape.

*Engineers can design safer structures because they understand the flammability of building materials.

Explanation:

Physical properties of the material can be define as the properties which can be observed or measured without changing the composition of the material. These properties includes texture, odor, color, boiling point, density, polarity, solubility, melting point, and others.

*Scientists can easily classify mixtures of unknown substances. : The mixtures of the metals can be separated by their physical properties such as color, shape and size of the metal particles.

*Engineers can design better bridges because they know how metal changes shape.: The change in shape is a physical property, understanding this property can help the engineers to design the bridges better.

*Engineers can design safer structures because they understand the flammability of building materials. :

Flammability is indicating towards the melting point of the building materials. Thus engineers must design the materials which is safe from flammability and must have a high melting point.

Veseljchak [2.6K]4 years ago

3 0

Answer:

*Engineers can design better bridges because they know how metal changes shape.

*Scientists can easily classify mixtures of unknown substances.

Explanation:

Tensile strength and the properties of mixtures are physical properties because the substances are not changed into different ones.

A. and C. are wrong. Combustion and other reactions are chemical properties because the substances are changed into different ones

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Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

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Q = 3,950.1 J = 3.9501 kJ

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Then 3.950.1 kJ of heat will be given by:

$=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol$

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

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2) Minimum mass of methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

$Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC$

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

$=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol$

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

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