Answer:
The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which s is the standard deviation of the sample.
So
The lower end of the interval is the mean subtracted by M. So it is 7.5 - 9.0125 = -...
There is not a negative number of hours. So the lower end of the interval is 0 hours.
The upper end of the interval is the mean added to M. So it is 7.5 + 9.0125 = 16.5125 hours.
The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).
Answer will be option 2nd.
S(-4,7), T(-7,0), U(-1,0)
Answer:
What are the options
Step-by-step explanation:
A model being 0.001 shaded would be 0.1% or 1/1000 of the whole model. 1 would equal the whole model being shaded, but that’s not the case. Instead, it’s in the thousandths, so that’s 1/1000 or 0.1% of the whole model shaded.
Answer:
Step-by-step explanation:
Let a is the width of the window and diameter of the semicircle and let h be height of the rectangular portion of the window
:
Perimeter:
2h + a + .5x*pi = 21
2h + 2.57a = 21
2h = 21 - 2.57a
h = (10.5-1.285a)
:
What would be the window with the greatest area;
Area = semicircle + rectangle
Radius = .5a
A = (.5*pi*(.5a)^2) + h*a
Replace h with (10.5-1.285a
A = (1.57*.25a^2) + x(10.5-1.285a)
A = .3927a^2 - 1.285a^2 + 10.5a
A = -.8923a^2 + 10.5a
Find the max area by finding the axis of symmetry; x = -b/(2a)
a = 5.88 meter is the width with the greatest area
:
Find the max area
A = -.8923(5.88^2) + 10.5(5.88)
A = -.8923(5.88^2) + 10.5(5.88)
A = -30.85 + 61.74
A = 30.89 sq/ft is max area
