How might you solve a problem that has both a fraction and a decimal in it

1 answer:

5 0

Well, one way is to convert one of the numbers to the other. For example, if I have 3/5 and 0.5, I could convert 3/5 to a decimal. So, I would have 0.6 (3/5 converted to a decimal), and 0.5. Next, I would just add the two together to get my answer of 1.1

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Where does f(x) = g(x)

olya-2409 [2.1K]

f(x) = g(x) at x = 2.

In order to find this, you look for where the two graphs intersect. In this case, they intersect at the point (2, 5). At this point, both f(x) and g(x) both equal 5. So to identify the point, we need to look at the x value of the ordered pair, which is x = 2.

3 0

4 years ago

Round 69581.491337 to the nearest thousand.

Anika [276]

Answer:

7000

Step-by-step explanation:

lets start with 695

9 is the thousand

you check the number next to 9

less then 4 let it rest

more than 5 let it soar

something like that lol

anyways since 5 is next to the 9 we round up from 9 to the next number which is 10

so that changes the whole number to 7000

hope this makes sense!

3 0

3 years ago

There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g

-BARSIC- [3]

The inequality $\mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$ gives the least number of buses, b, needed for the trip. The least number of buses is 9

Solution:

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.

Each bus can seat a maximum of 48.

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

The number of buses required “b” is given as:

$\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$

$\text { So, number of buses required } \geq \frac{432}{48}$

Number of buses required ≥ 9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality $\mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}}$ gives least count of busses and least count is 9.