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Mademuasel [1]
3 years ago
9

A restaurant offers 10 appetizers and 12 main courses. In how many ways can a person order a​ two-course meal? Use the Fundament

al Counting Principle with two groups of items.
Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

80 ways

Step-by-step explanation:

The first thing is to apply the Fundamental Counting Principle with two groups of items, in this case the multiplication rule is used.

In this case, what we should do is that, for every 1 main course there are 8 appetizers, but there are 10 main courses therefore:

8 * 10 = 80

There are 80 ways to combine appetizers and the main course

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Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.
Sladkaya [172]

Answer:

The solution is  \frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

Step-by-step explanation:

From the question

    The function given is  f(x) =  \frac{e^{2x}}{ 25 + e^{4x}} dx

The  indefinite integral is  mathematically represented as

          \int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx

Now  let  e^{2x} =  u

=>   \frac{du}{dx} 2e^{2x}

=>   2 e^{2x}dx =  du

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Now substituting for  u

\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

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