Ask question

Ask question

All categories

2 years ago

9

If the volume of the pyramid is 64 ft³; and the height is 16 ft, what is the base area measured in square feet?

2 answers:

Law Incorporation [45]2 years ago

8 0

The volume of a pyramid would be the base area times the height.
Given the height and volume we can find the base ares by dividing the volume by the height.

64 / 16 = 4

The base area is 4 square feet

In-s [12.5K]2 years ago

6 0

Answer: Base area would be 12 square feet.

Step-by-step explanation:

Since we have given that

Volume of pyramid = 64 ft³

Height of pyramid = 16 ft

As we know the formula for "Volume of pyramid":

$Volume=\dfrac{1}{3}\times Base\ area\times height\\\\64=\dfrac{1}{3}\times base\ area\times 16\\\\\dfrac{64\times 3}{16}=Base\ area\\\\12\ ft^2=Base\ area$

Hence, base area would be 12 square feet.

You might be interested in

What is the domain of the function y=cube root of x

mafiozo [28]

All real numbers. in interval notation, that's (<span><span>−∞</span>, ∞</span><span>). there isn't a value you could insert for "x" that would give you an error.</span>

3 0

3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

How many solutions does the equation -6y+13+9y=8y-3

Lina20 [59]

Answer:

Single Solution of 3.2 (16/5)

Step-by-step explanation:

3x = 8x -16 <--- I combine like terms.

-5x = -16

-16/-5 = x

x = 3.2

BTW Negative times a Negative equals a positive.

3 0

2 years ago

For the pair of similar triangles, find the value of x.

Murljashka [212]

Find the scale between sides xz and gh

18/4 = 4.5

Multiply the length of fh by the scale to find x

6 x 4.5 = 27

x = 27

7 0

2 years ago

4x+15y=10 3x+10y=5<br><br><br><br><br><br><br><br><br><br>please help

Kamila [148]

Answer: 7x+25y=15

Step-by-step explanation: combine all like terms

8 0

2 years ago