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leonid [27]
3 years ago
15

Calculate the wavelength of a body of mass 96.0 mg and moving with a velocity of 30.0 m/s. The value of Planck’s constant is 6.6

26 × 10–34 J s.
Chemistry
1 answer:
Katen [24]3 years ago
6 0

Answer:

vcvvvvvvvvvvvvvv

Explanation:

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C. the rock may have diferrent textures 

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How can you use continental drift hypothesis in a sentence
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Answer:

The largest bays have developed as a result of continental drift. With the loss of either of these, continental drift will come to a halt

Explanation:

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Ethyne (C2 H2 (g), Hf = 226.77 kJ/mol) undergoes complete combustion in the presence of oxygen to produce carbon dioxide
den301095 [7]
C₂H₂ + O₂ --> CO₂ + H₂O

when balanced

2C₂H₂ + 5O₂ --> 4CO₂ + 2H₂O
8 0
3 years ago
A solution is prepared by dissolving 8.75 grams of sodium chloride in enough volume of water to produce 112.0 grams of the NaCl
ICE Princess25 [194]

Answer : The percent by mass of the solution is 7.81 %

Explanation : Given,

Mass of NaCl = 8.75 g

Mass of solution = 112.0 g

Now we have to determine the percent by mass of the solution.

\text{Mass percent}=\frac{\text{Mass of NaCl}}{\text{Mass of solution}}\times 100

Putting values in above equation, we get:

\text{Mass percent}=\frac{8.75g}{112.0g}\times 100=7.81\%

Therefore, the percent by mass of the solution is 7.81 %

6 0
3 years ago
How many moles are represented by 3.01 x10^24 oxygen atoms?
asambeis [7]
<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u> </u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})
  2. Multiply/Divide:                \displaystyle 4.99834 \ mol \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

4.99834 mol O₂ ≈ 5.00 mol O₂

4 0
3 years ago
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