N2O4(g) 2NO2(g) Which of the following represents the Keq value? 0.18 0.0067 0.131 0.0046

you see a coin at the bottom of a fountain of water but when you reach for it it is in another place than it appears to be

Roman55 [17]

Objects in the fountain appear to be somewhere but isnt

6 0

2 years ago

on dr v’s bookshelf there are 23 science textbooks each with an average of 31 chapters of each chapter contains 5 pages how many

olga55 [171]

Answer:

There are 3600 pages to 2 significant figures

Explanation:

Working only with the information given, we have that there are 23 books each with about 31 chapters.

This means that if 1 book has 31 chapter, the 23 science books will have

31 X 23 chapters =713 chapters in total.

If each chapter contains 5 pages, for the 713 chapters we will have a total of 713 X 5 pages = 3565 pages.

Rounding off the answer to 2 significant figures , we are looking to have only two non-zero figures in our answer. To do this, we count two numbers from the left. This will be numbers 3 and 5.

Next, we check the net number after 5 to see if it is greater than 5 if it is, we will have to add the number (1 ) to the 5. This shows that we are approximating upwards, to account for the fact that that number has passed the middle point.

After this, we change the remaining two numbers (6 and 5) to zeroes.

This will give us 3600 pages.

8 0

3 years ago

Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,

Luda [366]

The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) = 16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0

2 years ago

CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.23-L flask at a certain temperature initially contains 27.2 g CO and 2.36 g H2.

irga5000 [103]

Answer: 5.70M

Explanation:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.05 g/mol.

To determine the amount of each compound in the reaction mixture we use the formula.

Amount in mol = reacting mass/molar mass.

Inputing the given values we have,

26.6 g CO x (1 mol / 28.01 g ) = 0.9496608354 mol of CO.

To calculate the concentration of CO we use C=n/v, where n=amount and v= volume of CO.

Inputing the values in the formula

[CO] = 0.9496608354 mol CO / 5.23 L = 0.18158 M CO

Repeating thesame procedure for H

Amount of H=2.36 g H2 x ( 1 mol / 2.02 g ) = 1.168316832 mol of H2

Concentration of H2 in the mixture

[H2] = 1.168316832 mol H2 / 5.23 L = 0.223388 M of H2

Amount of CH3OH is determine similarly using rmass/molar mass

8.66 CH3OH x (1 mol / 32.05 g ) = 0.2702028081 mol of CH3OH

Concentration of

[CH3OH] = 0.2702028081 mol CH3OH/ 5.23 L = 0.051664 M CH3OH

Now equilibrium constant is determined by

Kc = [CH3OH] / [CO] [H2]^2

=0.051664/0.18158×0.223388×0.223388.

=5.70

7 0

3 years ago

13. When iron nad is put in to a beaker containing copper sulphate solution.

svetlana [45]

Answer:

A simple displacement reaction occurs when an iron nail is immersed to a beaker containing copper sulphate solution.

a)

Iron is more reactive than copper. As a result a displacement reaction will take place. The ferrous or Fe (II) irons will move to the solution. The copper ions (Cu II) will get deposited on the nail. This will cause the colour to change from blue to green.

b)

The equation can be written as:

Fe (s) + CuSO4 (aq) -> FeSO4 (aq) + Cu (s)

c)

A chemical change can be described as a change that causes a substance to change to another form. Hence, this reaction is a chemical change.

4 0

2 years ago