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Sphinxa [80]
3 years ago
8

Calculate the root mean square velocity of nitrogen molecules at 25°c. a) 729 m/s b) 515 m/s c) 149 m/s d) 297 m/s

Chemistry
1 answer:
Elena L [17]3 years ago
3 0

Answer:

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s

Explanation:

given data

temperature = 25°c = 25 + 273 = 298 K

to find out

root mean square velocity of nitrogen molecules

solution

we know that root mean square velocity of gas is Vrms = \sqrt{\frac{3RT}{M}}      .......................1

mass of gas = M

universal gas constant = R

temperature = T

and we know mass of nitrogen = 28 g = 28 × 10^{-3} kg

Vrms = \sqrt{\frac{3RT}{M}}

Vrms = \sqrt{\frac{3(8.314)298}{28*10^{-3}}}

Vrms = 515.22 m/s

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s

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Why is a solution not a pure substance
Firlakuza [10]
It is not a pure substance, because a solution are mixed chemicals in a way that the molecules are not bonded with one another. Thus, separating them from compounds and elements, which are pure substances.
8 0
3 years ago
How many moles of nitrogen gas are present in a 28.9 dm3 temperature of 55.0 °C and a pressure of 144 kPa?
jeka57 [31]

Given :

Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .

Volume of container, V = 28.9 dm³ = 0.0289 m³ .

Pressure, P = 144 kPa = 144000 Pa .

To Find :

Number of moles of nitrogen  gas.

Solution :

We know, by ideal gas equation :

PV = nRT  ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .

n = \dfrac{PV}{RT}\\\\n = \dfrac{144000\times 0.0289}{8.31 \times 328} \ moles\\\\n = \dfrac{4161.6}{2725.68}\\\\n = 1.53 \ moles

Therefore, number of moles of nitrogen gas is 1.53 moles.

8 0
3 years ago
Which isotope will spontaneously decay and emit particles with a charge of +2?
VikaD [51]

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2) Beta-minus decay: It is a decay in which a beta particle is released. The  beta particle released has a mass number of 0 and a charge of (-1).

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0\beta

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form _{25}^{53}\textrm{Mn}

_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta

Option 2: This nuclei will undergo beta-minus decay process to form _{80}^{198}\textrm{Hg}

_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta

Option 3: This nuclei will undergo a beta minus decay process to form _{56}^{137}\textrm{Ba}

_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta

Option 4: This nuclei will undergo an alpha decay process to form _{85}^{216}\textrm{At}

_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha

Hence, the correct option is 4.

7 0
4 years ago
Read 2 more answers
Use the periodic table to find the number of valence electrons for calcium (Ca) aluminum (Al) rubidium (Rb) oxygen (O) sulfur (S
fgiga [73]

Answer:

Calcium (Ca) => 2

Aluminium (Al) => 3

Rubidium (Rb) => 2

Oxygen (O) => 2

Sulphur (S) => 2

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<em><u>Formulae</u></em>

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<em>Alumin</em><em>ium</em><em> </em><em>iodide</em><em> </em><em>:</em><em> </em>AlI3

<em>Rubidi</em><em>um</em><em> </em><em>sulphide</em><em> </em><em>:</em><em> </em>RbS

<em>Alum</em><em>inium</em><em> </em><em>oxide</em><em> </em><em>:</em><em> </em>Al2O3

4 0
3 years ago
Is this a compound,mixture or solution? (10 points)
goldenfox [79]

Answer:

it is a compound it is a solution when they say they are ablle to seperate it give out they did not mix it

Explanation:

6 0
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