Question

Calculate the root mean square velocity of nitrogen molecules at 25°c. a) 729 m/s b) 515 m/s c) 149 m/s d) 297 m/s

Answer 1

Answer:

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s

Explanation:

given data

temperature = 25°c = 25 + 273 = 298 K

to find out

root mean square velocity of nitrogen molecules

solution

we know that root mean square velocity of gas is Vrms = $\sqrt{\frac{3RT}{M}}$      .......................1

mass of gas = M

universal gas constant = R

temperature = T

and we know mass of nitrogen = 28 g = 28 × $10^{-3}$ kg

Vrms = $\sqrt{\frac{3RT}{M}}$

Vrms = $\sqrt{\frac{3(8.314)298}{28*10^{-3}}}$

Vrms = 515.22 m/s

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s