Answer:
1.70 g.cm⁻³
Solution:
Data Given;
Mass = 84.7 g
Volume = 49.6 cm³
Density = ?
Formula Used;
Density = Mass ÷ Volume
Putting values,
Density = 84.7 g ÷ 49.6 cm³
Density = 1.70 g.cm⁻³
The freezing point of water is 0° C. The Celsius (centigrade) scale is based off of water, with the freezing point at 0° and the boiling point at 100°. (Google will probably tell you this in 10 seconds, then you wouldn't have had to wait 7 hours!)
According to avogadro constant, the number of units in one mole of any substance contain 6.022 x10 ^23 atoms
therefore the number of o atoms in one mole of CuSO4 = 6.022 x 10 ^ 23
Answer:
just wait 3 minutes ill tell you the answer cause its in my book
Explanation:
