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Gekata [30.6K]
3 years ago
8

Please help due today!

Chemistry
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

it’s 2

Explanation:

yesssss

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Which of these processes indicates that smelting copper is a chemical change
BlackZzzverrR [31]

The correct answer is D:


it involves breaking molecular bonds between copper compounds .


The explanation :


-when we melt a copper it is a physical change because the substance is still copper and have the same shape.


- but for example Burning a copper it is a chemical change. Fire activates a chemical reaction between copper and oxygen.


-The oxygen in the air reacts with the copper and the chemical bonds are broken.


- the chemical change is changing the other compound bonded to the copper atoms.


So, the correct answer is D

5 0
3 years ago
Read 2 more answers
A 4 L sample of gas at 298 K and 2 atm contains 0.250 mol of gas. If we add another 0.250 mol of gas at the same pressure and te
andrey2020 [161]

Answer:

V_2=8L

Explanation:

Hello there!

In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Which can be solved for the final volume, V2, as shown below:

V_2=\frac{V_1n_2}{n_1}

Thus, by plugging in the given data, we obtain:

V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L

Regards!

4 0
3 years ago
Which statement describes a reaction at 298 K if AH = 31 kJ/mol, AS = 0.093
melisa1 [442]

Answer: (D) it is not spontaneous.

6 0
3 years ago
In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan
Advocard [28]

Answer:

Manganese, Fifth transition element

[X] 3d⁶ 4s¹

Iron, Sixth transition element

[X] 3d⁶ 4s²

Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

And according to Aufbau's principles that electrons fill the lower energy orbitals before they fill higher energy orbitals and Hund's Rule that states that electrons are fed singly to all the orbitals of a subshell before pairing occurs.

The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

So, in the new universe L, where there are six d orbitals, for manganese, the fifth transition metal, because half filled orbitals are more stable than partially filled orbitals (that woukd have been rhe case if we leave 5 electrons on the 3d orbital), the 4s orbital is filled to half of its capacity and the one electron removed from the 4s is used to fill the six 3d orbital to half of its capacity too.

For the sixth transition element, the new extra electron just fills the lower energy 4s orbital, leaving the six 3d orbitals all half-filled.

Hence, they both have ground state configurations of

- Manganese, Fifth transition element

[X] 3d⁶ 4s¹

- Iron, Sixth transition element

[X] 3d⁶ 4s²

Hope this Helps!!!

7 0
3 years ago
Our atmosphere is composed primarily of nitrogen and oxygen, which coexist at 25°C without reacting to any significant extent. H
Schach [20]

Answer:

a) T = 298 K

⇒ ΔG° = 173.1 KJ/mol

∴ ΔG° > 0.....the reaction occurs spontaneously in the reverse direction as given.

⇒ K = 4.542 E-31

b) T = 2000 K:

⇒ ΔG° = 1161.745 KJ/mol

ΔG°(2000K) > 0; We confirm that the reaction becomes more spontaneous as the temperature increases.

Explanation:

N2(g) + O2(g) → 2 NO(g)

a) ΔG°(298K) = 2 ΔG°fNO = 2(86.55 KJ/mol)

⇒ ΔG°(298K) = 173.1 KJ/mol

∴ ΔG° > 0.....the reaction is spontaneous

  • K = e∧(-ΔG°/RT)

∴ R = 8.314 E-3 KJ/mol.K

⇒ K = e∧(-173.1/(8.314E-3)(298)) = 4.542 E-31

b) T = 2000 K

  • ΔG° = - (LnK)(RT)

⇒ ΔG°(2000K) = - (Ln (4.542 E-31))(8.314 E-3 KJ/mol.K)(2000K)

⇒ ΔG°(2000K) = 1161.745 KJ/mol

∴ ΔG°(2000K) > 0; We confirm that the reaction becomes more spontaneous as the temperature increases

3 0
3 years ago
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