Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
Answer:
the answer is 2
Step-by-step explanation:
<span>this is the answer 43.6674</span>
Domain: (-1, 5)
Range: (-1, 3)
Explanation:
The domain covers the lowest and highest x value. You take the lowest number for the x and the highest number and that’s your domain. The range is covering y values, so you look at the lowest and highest point on your graph
Answer:
A: 5
B: 6
C: 3x^2 - 2x
D: 8
E: 22
Step-by-step explanation:
A: (-1)^2 + 4 = 5
B: (-4)^2 +4 = 16
2 x (-3) -4 = -10,
16-10=6
C: 3(x^2 + 4) = 3x^2 + 12
3x^2 + 12 -2x -4, simplify
3x^2 - 2x
D: g(3) = 2*3 -4 = 2
f(2) = 2^2 +4 = 8
E: f(3) = 3^2 + 4 = 13
g(13) = 2*13 - 4 = 22