Using sine formula we have
8/sin60 = x/sin30
hence x= 8/√3 = 4.62
Answer:
q = 10
Step-by-step explanation:
Answer:
Amy's car tank capacity is 16 gallons.
Step-by-step explanation:
Let the capacity of the tank be 'x'
Given:
Amount of gas in the car till it is refilled = 
Amount of gas added = 14 gallons.
We need to find the capacity of the tank.
Solution:
Now we can say that
Total Capacity of the tank is equal to sum of Amount of gas in the car till it is refilled and Amount of gas added.
framing in equation form we get;
Combining the like terms we get;
Now making the denominators common we will use L.C.M.
Now multiplying both side by 8 we get;
Now dividing both side by 7 we get;
Hence Amy's car tank capacity is 16 gallons.
In order to solve for this question, let's assign a couple variables.
The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.
From the given, we can already form two equations:
t + s = 36
("An exam... contains 36 questions")
2t + 6s = 148
("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")
Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:
2t + 6s = 148
t + 3s = 74
Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):
t + s = 36
t = 36 - s
This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:
t + 3s = 74
(36 - s) + 3s = 74
36 + 2s = 74
2s = 38
s = 19
Input 's' into our second equation to solve for 't':
t = 36 - s
t = 36 - 19
t = 17
There are 17 two-point questions and 19 six-point questions
- T.B.
Answer:
Step-by-step explanation:
2v-6=-14, add 6 to both sides
2v=-8, divide both sides by 2
v=-4
