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Kruka [31]
3 years ago
13

30 points!!!

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

SAS postulate

Step-by-step explanation:

AD (common)

AC = BD (both are diameters)

Angle COD = Ange AOD (vertically opposite angles)

Angle CAD = Angle BAD (angle on the circumference is half the angle at the centre)

Therefore, ABD and DCA are congruent by SAS postulate

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Which statement best describes the area of the triangle shown below?
Molodets [167]

Answer:

A triangle.

Step-by-step explanation:

5 0
3 years ago
Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
3 years ago
Write a quadratic equation in standard form with the given roots
stich3 [128]

{x}^{2}  -  \frac{15x}{2}   +  \frac{7}{2}

Step-by-step explanation:

So we go backwards, since we have x= 1/2 , 7

(x -  \frac{1}{2} )(x - 7)

Now we have to foil to get the quadratic

{x}^{2}  - 7x -  \frac{1}{2} x +  \frac{7}{2}

We must simplify the terms

{x}^{2}  -  \frac{14x}{2}  -  \frac{x}{2}  +  \frac{7}{2}

Our final result comes out to be

{x}^{2}  -  \frac{15x}{2}   +  \frac{7}{2}

5 0
2 years ago
PLEASE HELP ASAP
makkiz [27]

Answer:

5

Step-by-step explanation:

Since the difference in each term number is 5, we put 5 in the place of the star.

Formula for constant difference in a pattern: Tn= an+b

a is the difference while b is the number that comes before the 1st term. So, the equation to find the nth term is Tn=5n+4.

Hope this helps and please give a brainlist, thank you!

5 0
2 years ago
Five grams of sugar are added to a 40-gram serving of a breakfast cereal that is 10% sugar. What is the percent concentration of
tamaranim1 [39]
10g+0.10(40g)=14 grams of sugar.
7 0
3 years ago
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