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Rasek [7]
3 years ago
6

Given a mean of 61.2 and a standard deviation of 21.4, what is the z-score of the value 45 rounded to the nearest tenth?0.8−0.90

.9−0.8
Mathematics
1 answer:
kherson [118]3 years ago
6 0

Given: Mean μ = 61.2 and standard deviation σ =21.4

The Z score of the value x=45 is given by

Z = \frac{x - mean}{standard deviation}

Z = \frac{45 - 61.2 }{21.4}

Z = \frac{-16.2}{21.4}

Z = -0.757

The z-score value for 45 rounded to nearest tenth is -0.8

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Answer:
Area = 492.4 m²

Explanation:
The area of the triangle can be calculated using the side-angle-side method as follows:
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This rule is illustrated in the attached image.

Now, we have:
AB = 40 m
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angle B which is the angle included between AB and BC = 80 degrees

The given angle is included between the two given sides, therefore, we can apply the above rule to get the area.
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Hope this helps :)

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Read 2 more answers
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