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n200080 [17]
2 years ago
11

I need help on this problem plz I need help

Mathematics
1 answer:
Annette [7]2 years ago
4 0

Answer:

The number is 35

Step-by-step explanation:

Let x be the number

1/5 x + 3x

=

2x + 42                 Break the question into phrases and solve 1 phrase at a time.

1/5 = 0.2

0.2x + 3x = 2x + 42              Combine the left

3.2x = 2x + 42                       Subtract 2x from both sides

3.2x - 2x = 42                        Combine

1.2x = 42                                Divide by 1.2

x = 42/1.2

x = 35

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2 years ago
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Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute
Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so \mu = 35

Variance = 81. The standard deviation is the square root of the variance, so \sigma = \sqrt{81} = 9.

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, z = -0.44 has a pvalue of 0.333. So what is the value of X when z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{X - 35}{9}

X - 35 = -3.96

X = 31.04

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

P = P_{1} + P_{2}

P_{1} is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of X = 40.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 35}{9}

Z = 0.61

Z = 0.61 has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if P_{1} = 100% - 72.91% = 27.09% = 0.2709

P_{2} is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

X = 38.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{38.5 - 35}{9}

Z = 0.39

Z = 0.39 has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if P_{1} = 100% - 65.17% = 34.83% = 0.3483

So:

P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

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3 years ago
The expression(x^3)(x^-17) is equivalent to (n^x). What is the value of n?
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Answer:5000 million

Step-by-step explanation:

You have to multiple ok

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iVinArrow [24]

The alpha level should always be set to 0.05.

The supplied statement;

How should you select the alpha() level when doing a significance test in practice,

⇒ Use a higher alpha when the consequences of wrongly rejecting the null hypothesis are more severe. Select alpha () = 0.05 in every situation since it is the best option. Use a smaller alpha when the consequences of wrongly rejecting the null hypothesis are more severe.

To learn more about significance test click here:

brainly.com/question/12972662

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Answer:

(2,-4)

Step-by-step explanation:

-4+2=-2

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