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Furkat [3]
3 years ago
13

What is the simplest form of 2√3/ √6 A. √2 B. √3 C. 3√2 D. 2√3

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0

A

using the laws of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

\sqrt{a} × \sqrt{a} = a

Rationalise the denominator by multiplying numerator/ denominator by \sqrt{6}

2\sqrt{3} / \sqrt{6} × \sqrt{6} / \sqrt{6}

= 2\sqrt{18} / 6 = (2 × 3\sqrt{2}) / 6 = \sqrt{2} → A




STatiana [176]3 years ago
3 0

The answer is:

A) √2

Explanation:

2√3/ √6

=2/√2

= 2√2/√2√2

= 2√2/2

= √2


Hope it helps!

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(6x+5)-(3x+10)<br> how to solve this question?
Sveta_85 [38]

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3x-5

Step-by-step explanation:

(6x+5)-(3x+10) = 6x+5-3x-10

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According to a state law for vehicles traveling on state roads, the maximum total weight of a vehicle and its contents depends o
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Inequalities are used to show the relationship between unequal expressions.

The inequalities that represent the maximum weights are:

  • <em>2 axles - </em>x \le 40000<em>.</em>
  • <em>3 axles - </em>x \le 60000<em>.</em>
  • <em>4 axles - </em>x \le 80000<em>.</em>

<em />

Let the maximum weight be represented with x

In inequality, maximum means less than or equal to i.e. \le

<u>(a) 2 axles</u>

The maximum weight, here is 40000.

So, the inequality is:

x \le 40000

<u>(b) 3 axles</u>

The maximum weight, here is 60000.

So, the inequality is:

x \le 60000

<u>(c) 4 axles</u>

The maximum weight, here is 80000.

So, the inequality is:

x \le 80000

<em>See attachment for the graphs of each inequality</em>

Read more about inequalities at:

brainly.com/question/11612965

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