3t=4s+5 (s=side of square, t= side of triangle)
s=t-3, t=s+3, using this value for t in the first equation gives us:
3(s+3)=4s+5
3s+9=4s+5
-s=-4
s=4
so the side length of the square is 4cm and the area of a square is just s^2
A=16cm^2
Answer:
The distance between the top of the well and the bottom of the well was 12 1/2
Step-by-step explanation:
(a.k.a B) i did it and got it right :)
If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:
(true for <em>y</em> between -π/2 and π/2)
Now take the derivative of both sides and solve for it:
On the graph, we can see that when x=1, y=0.
But we don't even need to bother opening the attachment
and studying the graph !
In your question, you said that one point on the function is (1, 0) .
That means that when 'x' is 1, 'y' is zero. And there you are !
