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Ainat [17]
3 years ago
15

A cosine function has a period of 5, a maximum value of 20, and a minimum value of 0. The function is not a reflection of its pa

rent function over the x-axis.
Which function could be the function described?

A: f(x)=10cos(2π/5 x)+10
B: f(x)=10cos(5x)−10
C: f(x)=−10cos(5x)+10
D: f(x)=−10cos(2π/5 x)+10

Mathematics
1 answer:
Alika [10]3 years ago
7 0

Answer:

  A:  f(x)=10cos(2π/5 x)+10

Step-by-step explanation:

The coefficient of x in the cosine argument of the function will be 2π/period. Since the period is 5, the coefficient is 2π/5. This observation eliminates choices B and C.

The description "not a reflection of the parent function over the x-axis" means the multiplier of the cosine function is not negative, eliminating choice D.

The remaining choice A matches the description.

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Suppose f(x)=x^2. What is the graph of g(x)=1/2f(x)?
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Answer:

  see attached

Step-by-step explanation:

The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).

The graph of g(x) is attached.

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3 years ago
The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the pop
NikAS [45]

Answer:

  • p(t) = 100×1.0153^(12t)
  • 1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

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  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

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