To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
1.60/20 =0.08
0.08 per pen
Answer:
D. 32
Step-by-step explanation:
116 + 2b = 180
2b = 64
b = 32
2x X 54 is going to be 108x
since both are positive you will get a positive #
54 X 2 is 108
If I'm understanding this correctly:
Tiger consumes 18lb/day of food. If we want to calculate how much is consumed in 28 days, assuming that rate is consistent, the answer is 18*28 = 504lb of food.
